MendelSchmiedekamp comments on Money pumping: the axiomatic approach - Less Wrong

12 Post author: Stuart_Armstrong 05 November 2009 11:23AM

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Comment author: MendelSchmiedekamp 05 November 2009 06:27:38PM 0 points [-]

Sorry I left this out. It's a huge simplification, but treat the set of p as a discrete subset set in the standard topology.

Comment author: Stuart_Armstrong 06 November 2009 08:13:18AM 0 points [-]

And that is discontinuous; but you can model it by a narrow spike around the value of p, making it continuous.

Comment author: Stuart_Armstrong 05 November 2009 06:39:38PM 0 points [-]

Hum, this seems to imply that the set of p is a finite set...

Still doesn't change anything about the independence violation, though.

Comment author: MendelSchmiedekamp 06 November 2009 03:18:34PM *  1 point [-]

But does doesn't the money pump result for non-independence rely on continuity? Perhaps I missed something there.

(Of note, this is what happens when I try to pull out a few details which are easy to relate and don't send entirely the wrong intuition - can't vouch for accuracy, but at least it seems we can talk about it.)

Comment author: Stuart_Armstrong 06 November 2009 05:07:15PM *  0 points [-]

Actually, I realised you didn't need continuity at all. See the addendum; if you violate independence, you can be weakly money-pumped even without continuity (though the converse may be false).