Unknowns comments on Drawing Two Aces - Less Wrong

14 Post author: Eliezer_Yudkowsky 03 January 2010 10:33AM

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Comment author: Unknowns 03 January 2010 11:24:02AM *  13 points [-]

Argument 2 is correct. When the person replies "Yes," after choosing randomly, you learn not only that he has the ace of spades, but also that on one trial, he selected it after choosing randomly from his aces. This makes the combinations "AS, 2C" and "AS, 2D" more probable than "AS, AH", since the first two combinations give a 100% chance of a positive response, while the third gives only a 50% chance of a positive response. So each of the first two combinations is twice as likely as the third, so the probability of the third combination, namely two aces, goes to 1/5.

Comment author: cousin_it 03 January 2010 12:04:21PM *  7 points [-]

I reached the same solution.

This looks like a riff on the Monty Hall problem, whose solution also hinges on the fact that the host opens a door randomly or non-randomly depending on your initial choice.

Comment author: MatthewB 03 January 2010 12:41:24PM 0 points [-]

This is exactly what I thought when I read the problem.