cabalamat comments on Drawing Two Aces - Less Wrong

14 Post author: Eliezer_Yudkowsky 03 January 2010 10:33AM

You are viewing a comment permalink. View the original post to see all comments and the full post content.

Comments (84)

You are viewing a single comment's thread.

Comment author: cabalamat 05 January 2010 07:19:37AM *  3 points [-]

The probability is 1/5 (as independently calculated by me). I've no idea if argument 2 is correct, because I don't understand it. My reasoning:

There are 6 combinations of 2 cards: AsAh, As2c, As2d, Ah2c, Ah2d, 2c2d.

Of these, only the first 3 (AsAh, As2c, As2d) could I have answered yes to both questions (assuming I'm not lying, wihch is outside the context).

But if I have AsAh, only 1/2 the time would I have answered yes to the second question. So AsAh needs 1/2 the weight of the other 2 possibilities.

So the probability is (1/2)/(2+1/2) = 1/5.