Have some Omega thought experiments been one shot, never to be repeated type deals or is my memory incorrect?
Yes I wasn't thinking through what would happen when the ith digit wasn't 0. You can't switch to one boxing in that case because you don't know when that would be, or rather when you see an empty box you are forced to do the same as when you see a full box due to the way the game is set up.
Have some Omega thought experiments been one shot, never to be repeated type deals or is my memory incorrect?
Yes, and that's the intent in this example as well. Still, it can be useful to look at the expected distribution of outcomes over a large enough number of trials that have the same structure, in order to infer the (counterfactual) probabilities that apply to a single trial.
According to Ingredients of Timeless Decision Theory, when you set up a factored causal graph for TDT, "You treat your choice as determining the result of the logical computation, and hence all instantiations of that computation, and all instantiations of other computations dependent on that logical computation", where "the logical computation" refers to the TDT-prescribed argmax computation (call it C) that takes all your observations of the world (from which you can construct the factored causal graph) as input, and outputs an action in the present situation.
I asked Eliezer to clarify what it means for another logical computation D to be either the same as C, or "dependent on" C, for purposes of the TDT algorithm. Eliezer answered:
I replied as follows (which Eliezer suggested I post here).
If that's what TDT means by the logical dependency between Platonic computations, then TDT may have a serious flaw.
Consider the following version of the transparent-boxes scenario. The predictor has an infallible simulator D that predicts whether I one-box here [EDIT: if I see $1M]. The predictor also has a module E that computes whether the ith digit of pi is zero, for some ridiculously large value of i that the predictor randomly selects. I'll be told the value of i, but the best I can do is assign an a priori probability of .1 that the specified digit is zero.