Quantum coinflips work even if Omega can predict them. It's like a branch-both-ways instruction. Just measure some quantum variable, then measure a noncommuting variable, and voila, you've been split into two or more branches that observe different results and thus can perform different strategies. Omega's perfect predictor tells it that you will do both strategies, each with half of your original measure. There is no arrangement of atoms (encoding the right answer) that Omega can choose in advance that would make both of you wrong.
I agree, and for this reason whenever I make descriptions I make Omega's response to quantum smart-asses and other randomisers explicit and negative.
According to Ingredients of Timeless Decision Theory, when you set up a factored causal graph for TDT, "You treat your choice as determining the result of the logical computation, and hence all instantiations of that computation, and all instantiations of other computations dependent on that logical computation", where "the logical computation" refers to the TDT-prescribed argmax computation (call it C) that takes all your observations of the world (from which you can construct the factored causal graph) as input, and outputs an action in the present situation.
I asked Eliezer to clarify what it means for another logical computation D to be either the same as C, or "dependent on" C, for purposes of the TDT algorithm. Eliezer answered:
I replied as follows (which Eliezer suggested I post here).
If that's what TDT means by the logical dependency between Platonic computations, then TDT may have a serious flaw.
Consider the following version of the transparent-boxes scenario. The predictor has an infallible simulator D that predicts whether I one-box here [EDIT: if I see $1M]. The predictor also has a module E that computes whether the ith digit of pi is zero, for some ridiculously large value of i that the predictor randomly selects. I'll be told the value of i, but the best I can do is assign an a priori probability of .1 that the specified digit is zero.