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Gary_Drescher comments on A problem with Timeless Decision Theory (TDT) - Less Wrong
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No, but it seems that way because I neglected in my OP to supply some key details of the transparent-boxes scenario. See my new edit at the end of the OP.
So, with those details, that resolves to "I get $0". This makes D(M) = !M the unambiguous 'correct' decision function.