By "unsolvable" I mean that you're screwed over in final outcomes, not that TDT fails to have an output.
Oh ok. So it's unsolvable in the same sense that "Choose red or green. Then I'll shoot you." is unsolvable. Sometimes choice really is futile. :) [EDIT: Oops, I probably misunderstood what you're referring to by "screwed over".]
The interesting part of the problem is that, whatever you decide, you deduce facts about the background such that you know that what you are doing is the wrong thing.
Yes, assuming that you're the sort of algorithm that can (without inconsistency) know its own choice here before the choice is executed.
If you're the sort of algorithm that may revise its intended action in response to the updated deduction, and if you have enough time left to perform the updated deduction, then the (previously) intended action may not be reliable evidence of what you will actually do, so it fails to provide sound reason for the update in the first place.
According to Ingredients of Timeless Decision Theory, when you set up a factored causal graph for TDT, "You treat your choice as determining the result of the logical computation, and hence all instantiations of that computation, and all instantiations of other computations dependent on that logical computation", where "the logical computation" refers to the TDT-prescribed argmax computation (call it C) that takes all your observations of the world (from which you can construct the factored causal graph) as input, and outputs an action in the present situation.
I asked Eliezer to clarify what it means for another logical computation D to be either the same as C, or "dependent on" C, for purposes of the TDT algorithm. Eliezer answered:
I replied as follows (which Eliezer suggested I post here).
If that's what TDT means by the logical dependency between Platonic computations, then TDT may have a serious flaw.
Consider the following version of the transparent-boxes scenario. The predictor has an infallible simulator D that predicts whether I one-box here [EDIT: if I see $1M]. The predictor also has a module E that computes whether the ith digit of pi is zero, for some ridiculously large value of i that the predictor randomly selects. I'll be told the value of i, but the best I can do is assign an a priori probability of .1 that the specified digit is zero.