byrnema comments on Self-indication assumption is wrong for interesting reasons - Less Wrong
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In a nutshell, the simplified problem in the post was this: You have a hotel with green and red rooms, 4 of one color and 1 of another. If you ask an observer at random which case they think it is, on average they will be correct 80% of the time. However, if you ask someone in a green room, they will only be correct 50% of the time.
(Here's the detailed explanation. Skip if you prefer.)
Suppose you ask a random person. 10 trials would like this on average:
On average, the observers are correct 80% of the time because the frequency of a red verses green observer is information about the true distribution.
Suppose you ask a person in a green room. In this case, 10 trials on average would like this:
Now, the observers are only correct 50% of the time because their distribution doesn't reflect the true distribution. You skewed the frequency of green roomers by pre-selecting green.
This was my summary solution to the problem: