= 27d567bc2d48d9f40e9ccc20ea370b15)
thomblake comments on A Proof of Occam's Razor - Less Wrong
You are viewing a comment permalink. View the original post to see all comments and the full post content.
= 783df68a0f980790206b9ea87794c5b6)
Loading…= b715d02e85f7b3b4ae65ca3d3e450868)
Subscribe to RSS Feed
Powered by Reddit
= f037147d6e6c911a85753b9abdedda8d)
You are viewing a comment permalink. View the original post to see all comments and the full post content.
Comments (121)
Regardless of the probability distribution.
If one has any assignment of probabilities to an infinite series of mutually exclusive hypotheses H1, H2, ..., then for every epsilon > 0 there is an N such that every hypothesis after the Nth has probability less than epsilon. In fact, there is an N such that the sum of the probabilities of all the hypotheses after the Nth is less than epsilon.
Hmm... maybe I was reading your claim as stronger than you intended. I was imagining you were claiming that property would hold for any finite enumerated subset, which clearly isn't what you meant.
If the sum of every term in a sequence after the Nth one is less than epsilon, then the sum of every term in any subsequence after the Nth one is also less than epsilon.
Right, but that isn't what I meant - it is not necessarily the case that for every n, every hypothesis after the nth has probability less than that of the the nth hypothesis. Obviously - which is why I should have noticed my confusion and not misread in the first place.