AlephNeil comments on The Smoking Lesion: A problem for evidential decision theory - Less Wrong
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I don't understand why the Smoking Lesion is a problem for evidential decision theory. I would simply accept that in the scenario given, you shouldn't smoke. And I don't see why you assert that this doesn't lessen your chances of getting cancer, except in the same sense that two-boxing doesn't lessen your chances of getting the million.
I would just say: in the scenario give, you should not smoke, and this will improve your chances of not getting cancer.
If you doubt this, consider if the correlation were known to be 100%; every person who ever smoked up till now, had the lesion and developed cancer, while every person who did not smoke, did not have the lesion. This was true also of people who knew about the Lesion. Do you still say it's a good idea to smoke?
You're correct that if the correlation were known to be 100% then the only meaningful advice one could give would be not to smoke. However, it's important to understand that "100% correlation" is a degenerate case of the Smoking Lesion problem, as I'll try to explain:
Imagine a problem of the following form: Y is a variable under our control, which we can either set to k or -k for some k >= 0 (0 is not ruled out). X is an N(0, m^2) random variable which we do not observe, for some m >= 0 (again, 0 is not ruled out). Our payoff has the form (X + Y) - 1000(X + rY) for some constant r with 0 <= r <= 1. Working out the optimal strategy is rather trivial. But anyway, in the edge cases: If r = 0 we should put Y = k and if r = 1 we should put Y = -k.
Now I want to say that the case r = 0 is analogous to the Smoking Lesion problem and the case r = 1 is analogous to Newcomb's problem (with a flawless predictor):
ETA: Perhaps this analogy can be developed into an analysis of the original problems. One way to do it would be to define random variables Z and W taking values 0, 1 such that log(P(Z = 1 | X and Y)) / log(P(Z = 0 | X and Y)) = a linear combination of X and Y (and likewise for W, but with a different linear combination), and then have Z be the "player's decision" and W be "Omega's decision / whether person gets cancer". But I think the ratio of extra work to extra insight would be quite high.