humpolec comments on A note on the description complexity of physical theories - Less Wrong

19 Post author: cousin_it 09 November 2010 04:25PM

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Comment author: Jack 11 November 2010 10:42:12AM *  0 points [-]

I think that works actually. If you observe 30 quantum heads in a row you have strong evidence in favor of MWI. The quantum suicide thing is just a way of increasing the proportion of future you's that have this information.

Comment author: humpolec 11 November 2010 11:14:33AM *  2 points [-]

If you observe 30 quantum heads in a row you have strong evidence in favor of MWI.

But then if I observed any string of 30 outcomes I would have strong evidence for MWI (if the coin is fair, "p" for any specific string would be 2^-30).

Comment author: Jack 12 November 2010 01:30:32AM 0 points [-]

You have to specify a particular string to look for before you do the experiment.

Comment author: humpolec 12 November 2010 06:45:15AM 0 points [-]

Sorry, now I have no idea what we're talking about. If your experiment involves killing yourself after seeing the wrong string, this is close to the standard quantum suicide.

If not, I would have to see the probabilities to understand. My analysis is like this: P(I observe string S | MWI) = P(I observe string S | Copenhagen) = 2^-30, regardless of whether the string S is specified beforehand or not. MWI doesn't mean that my next Everett branch must be S because I say so.

Comment author: humpolec 11 November 2010 11:17:54AM *  0 points [-]

The reason why this doesn't work (for coins) is that (when MWI is true) A="my observation is heads" implies B="some Y observes heads", but not the other way around. So P(B|A)=1, but P(A|B) = p, and after plugging that into the Bayes formula we have P(MWI|A) = P(Copenhagen|A).

Can you translate that to the quantum suicide case?