Vladimir_Nesov comments on Counterfactual Calculation and Observational Knowledge - Less Wrong

11 Post author: Vladimir_Nesov 31 January 2011 04:28PM

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Comment author: Vladimir_Nesov 04 February 2011 11:39:34AM *  0 points [-]

Or it is the correct utility if Omega also replaces the result in worlds where the parity of Q is different

Since you don't know what parity of Q is, you can't refer to the class of worlds where it's "the same" or "different", in particular because it can't be different. So again, I don't know what you describe here.

(It's still correct to talk about the sets of possible worlds that rely on Q being either even or odd, because that's your model of uncertainty, and you are uncertain about whether Q is even or odd. But not of sets of possible worlds that have your parity of Q, just as it doesn't make sense to talk of the actual state of the world (as opposed to the current observational event, which is defined by past observations).)

Comment author: FAWS 04 February 2011 03:44:18PM 0 points [-]

Since you don't know what parity of Q is, you can't refer to the class of worlds where it's "the same" or "different", in particular because it can't be different. So again, I don't know what you describe here.

I'm merely trying to exclude a possible misunderstanding that would mean both of us being correct in the version of the problem we are talking about. Here's another attempt. The only difference between the world Omega shows up in and the counterfactual worlds Omega affects regarding the calculator result is whether or not the calculator malfunctioned, you just don't know on which side it malfunctioned. Is that correct?

Comment author: Vladimir_Nesov 04 February 2011 05:57:07PM *  0 points [-]

Sounds right, although when you speak of the only difference, it's easy to miss something.