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Sniffnoy comments on Value Stability and Aggregation - Less Wrong
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It's kind of silly, but I'm thinking of the subset games where you only ever get 2 options.
If I and my opponent only have A(paper), B(rock) to choose from, then always A > B. Likewise B>C, C>A.
I'm not sure how this maps to larger practical situations, but one may be able to make some analogy out of it.
Actually, the rock papers scissors comes up in strategy games frequently.
If you and your opponent only have paper and rock to choose from, this is correct. But if that is the case, then you are not considering two options within the existing game, you are considering a different game entirely. To equate your preference for paper over rock in a game of Rock-Paper, with a preference for paper over rock in a game of Rock-Paper-Scissors, is a confusion. In that case, the scenario would read, "My opponent can throw Rock, Paper, or Scissors; if we assume I don't want to go Scissors (but my opponent does not know this), what should I do?" Within the given game, there are no intransitive preferences.