Willingness to pay Omega depends on having arbitrarily high confidence in his predictions
No. Paying is the winning strategy in the version where the predictor is correct only with probability, say, 0.8, too. ie.
P(o=AWARD) = 0.8*P(a=PAY)+0.2*P(a=REFUSE)
(blink)
You're right; I'm wrong. Clearly I haven't actually been thinking carefully about the problem.
Thanks.
This problem is roughly isomorphic to the branch of Transparent Newcomb (version 1, version 2) where box B is empty, but it's simpler.
Here's a diagram: