RichardKennaway comments on The Bias You Didn't Expect - Less Wrong

92 Post author: Psychohistorian 14 April 2011 04:20PM

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Comment author: TheOtherDave 09 October 2012 01:05:26PM 0 points [-]

You've lost me completely.

If we're talking about the probabilities of X and Y, as you say here, then the evidence against them lowers those probabilities, and the fact that the debate in your abstract example is over whether X or Y is correct doesn't change that. It is a situation where both are less likely than they were before C was known.

If your basic point is consistent with that, then I do not understand your basic point. It sure sounds to me like your basic point was that C made one of those assertions more likely, which is false.

Comment author: RichardKennaway 09 October 2012 03:27:49PM *  1 point [-]

I believe brazil84 is describing this:

P(X | C & (X v Y)) > P(X | X v Y)
P(Y | C & (X v Y)) < P(Y | X v Y)

while you are describing this:

P(X | C) < P(X)
P(Y | C) < P(Y)

All four of these statements can be true.

Comment author: TheOtherDave 09 October 2012 03:39:13PM 0 points [-]

(nods)
See also alejandro1's sibling comment and my reply.