Constant comments on The Many Worlds of Hugh Everett - Less Wrong

22 Post author: johnclark 22 April 2011 03:26PM

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Comment author: [deleted] 23 April 2011 07:37:51AM 4 points [-]

You can set up a one to one correspondence between all the points on a line (or in a square or in a cube) and all the clock faces a working clock can produce but you cannot do the same with all possible clock faces.

The set of all clock faces a working clock can produce - call this the set of all valid clock faces - has the same topology (and cardinality) as a circle. The set of all possible clock faces has the same topology (and cardinality) as a 2-dimensional torus.

However, the cardinality of a 2-dimensional torus is the same as the cardinality of a square, which is the same as the cardinality of a line (as you yourself recognize), which is the same as the cardinality of a circle.

Therefore the set of all valid clock faces has the same cardinality as the set of all possible clock faces.

the faces a working clock can produce is just ONE way all real numbers can be paired together, the power set is ALL the ways 2 real numbers can be paired together, it has a larger cardinality than the points on a line and is the number of all possible clock faces.

A power set indeed has a larger cardinality than the set it is a power set of. However, the set of all possible clock faces is not the power set of the set of all valid clock faces.

Comment author: johnclark 23 April 2011 05:47:30PM -1 points [-]

The set of all clock faces a working clock can produce - call this the set of all valid clock faces - has the same topology (and cardinality) as a circle.

Yes.

The set of all possible clock faces has the same topology (and cardinality) as a 2-dimensional torus.

Show me.

John K Clark

Comment author: [deleted] 23 April 2011 06:07:36PM 5 points [-]

There are two hands, an hour hand and a minute hand. The set of all possible positions that the hour hand can take describes a circle. The same is true of the minute hand: its set of all possible positions describes a circle. Consequently, the set of all ordered pairs of possible positions (h,m), where h is the position of the hour hand and m is the position of the minute hand, is the Cartesian product of the two individual sets, and thus the Cartesian product of two circles. This is a two-dimensional torus.

Comment author: AdeleneDawner 24 April 2011 12:29:32AM 0 points [-]

Did you take into account that the positions of the two hands are not independent? When the hour hand of a given clock is at its 12:00:00 position, there's only one possible location of the minute hand for that clock, and this is true for any position of the hour hand.

Comment author: Cyan 24 April 2011 12:55:03AM *  2 points [-]

If you read elsewhere in the thread, you'll see that johnclark draws a distinction between all possible clock faces and "valid clock faces", i.e., those that obey the constraint you describe. Constant is addressing the former, not the latter.

Comment author: [deleted] 24 April 2011 01:35:18AM 1 point [-]

Yes. Thanks.

Comment author: AdeleneDawner 24 April 2011 12:56:44AM 0 points [-]

Ah. Okay.

Comment author: wedrifid 24 April 2011 08:19:27AM 1 point [-]

Good point. The minute hand is entirely redundant.