JGWeissman comments on Bayesians vs. Barbarians - Less Wrong

51 Post author: Eliezer_Yudkowsky 14 April 2009 11:45PM

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Comment author: Alicorn 23 March 2011 11:40:08PM *  1 point [-]

"if you want to average 40 mph on a trip, and you averaged 20 mph for the first half of the route, how fast do you have to go on the second half of the route?"

How do you answer this question?

Edit: MBlume kindly explained offsite before the offspring comments were posted. Er, sorry to have wasted more people's time than I needed.

Comment author: JGWeissman 23 March 2011 11:56:23PM 2 points [-]

Suppose the total trip is a distance d.

d = (average speed) (time)
time = d / (average speed)

So if your average speed is 40 (mph), your total time is d/40.

You have already travelled half the distance at speed 20 (mph), so that took time (d/2)/20 = d/40. Your time left to complete the trip is your total time minus the time spent so far: d/40 - d/40 = 0. In this time you have to travel the remaining distance d/2, so you have travel at a speed (d/2)/0 = infinity, which means it is impossible to actually do.