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orthonormal comments on Decision Theory Paradox: PD with Three Implies Chaos? - Less Wrong
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"Gur GQG ntragf qba'g ybfr. Lbh tnir gurz fbzrguvat gb znkvzvfr naq gurl znkvzvfrq vg. Gurl qvq abg znkvzvfr na ragveryl qvssrerag ceboyrzf bs znxvat gurve qrfpraqnagf unir gur uvturfg cebcbegvba bs gur cbchyngvba be znxvat gurve trareny pynff bs qrpvfvba gurbevfg unir gur uvturfg cebcbegvba." is the natural answer to 3, and question 4 is distinguished from question 3 and I think elicits a better answer that adds to the discussion in a way the answer to question 3 wouldn't if one were to say "that which was wrong with question 3, is also wrong with question 4". An autistic reading of that answer applies to question 4, and isn't wrong, but there's more to say.
"Gurl qvqa'g ybbx nurnq" is something you can't say about 3, that you can say about 4, for had they done that in 3, it wouldn't increase their score, while they need to do that in 4 to increase their score (above zero).
Gung'f abg dhvgr evtug, yrffqnmrq; va gur fvghngvba jvgu GQGf naq QrsrpgObgf, gur GQGf jbhyq vapernfr gurve cbchyngvba snfgre va gur ybat eha vs gurl ershfrq gb nyybj QrsrpgObgf gb serr-evqr. Nyfb, vs gurl qvq fb, gurve cebcbegvba jbhyq evfr gb bar vafgrnq bs fgvpx ng bar unys.
Good point. I missed that since the number goes to infinity as the trials do regardless.
If you could devise a problem where the obvious flaw in "GQG fubhyq orng gur fbpxf bss bs QrsrpgObgf va nal snve svtug." alone would be implicated, that would be good, since it really is a different one than snvyvat gb ybbx nurnq.