hairyfigment comments on Stupid Questions Open Thread Round 2 - Less Wrong

15 Post author: OpenThreadGuy 20 April 2012 07:38PM

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Comment author: hairyfigment 20 April 2012 09:12:34PM 0 points [-]

Well-ordering of R is enought to create unmeasurable set.

Does a well-ordering on the constructable version of R provably do this? I fear I can't tell if you've addressed my question yet.

Comment author: vi21maobk9vp 21 April 2012 05:44:20AM 1 point [-]

Constructible version of R (if it is inside R and not the whole R) is just like Q: dense, small part of the whole, and usually zero-measure. So, this construction will yield something of measure zero if you define measure on the whole R.