Incorrect comments on Stupid Questions Open Thread Round 2 - Less Wrong

15 Post author: OpenThreadGuy 20 April 2012 07:38PM

You are viewing a comment permalink. View the original post to see all comments and the full post content.

Article Navigation

Comments (208)

Comments (208)

Sort By: Best

Show:

You are viewing a single comment's thread. Show more comments above.

Comment author: Incorrect 20 April 2012 11:13:55PM * 1 point [-]

Is this a correct statement of what a well-ordering of R is?

$\exists A (\text{total-order}(A, \mathbb{R}) \land \forall B (B \subseteq \mathbb{R} \land B \neq \emptyset \implies \exists x \in B \forall y \in B ((x \preceq y) \in A))) \forall A \forall B (\text{total-order}(A, B) \iff \forall a \forall b \forall c(a, b, c \in B \implies (((a \preceq b) \in A \lor (b \preceq a) \in A) \land ((a \preceq b) \in A \land (b \preceq a) \in A \implies a = b) \land ((a \preceq b) \in A \land (b \preceq c) \in A \implies (a \preceq c) \in A))))$

Comment author: gjm 21 April 2012 12:06:00AM -1 points [-]

Looks OK to me, though I can't guarantee that there isn't a subtle oops I haven't spotted. (Of course it assumes you've got some definition for what sort of a thing (a <= b) is; you might e.g. use a Kuratowski ordered pair {{a},{a,b}} or something.)

Incorrect comments on Stupid Questions Open Thread Round 2 - Less Wrong

Article Navigation

Comments (208)

Nearest Meetups

Virtual Study Room

Recent Comments

Recent Posts

Recent Rationality Quotes

Recent Wiki Edits

Top Contributors, 30 Days

Recent Karma Awards

Comments (208)

Top Contributors, 30 Days

You'll need to login or register to do that

(Don't worry, it only takes a few seconds)

Create

Login