VKS comments on Rationality Quotes May 2012 - Less Wrong

6 Post author: OpenThreadGuy 01 May 2012 11:37PM

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Comment author: VKS 02 May 2012 10:02:04PM *  4 points [-]

3^odd = 3 mod 4

so it ends in 7.

(but I repeat myself)

Comment author: Zack_M_Davis 02 May 2012 10:05:08PM *  0 points [-]

I think you're mistaken. Counterexample: 3^9 = 19683.

Comment author: JGWeissman 02 May 2012 10:09:33PM 0 points [-]

19683 = 3 mod 4

Comment author: VKS 02 May 2012 10:12:36PM *  1 point [-]

and 3^19683 = 150 ... 859227, which ends in 7.

( The full number is 9392 digits long, which messes up the spacing in these comments. )

Comment author: Zack_M_Davis 02 May 2012 10:18:09PM *  0 points [-]

Oh, sorry; I agree that odd powers of three are 3 mod 4, but I had read VKS as claiming that odd powers of three had a final digit of seven; I probably misunderstood the argument. [EDIT: Yes, I was confused; I understand now.]

Comment author: VKS 02 May 2012 10:24:57PM 2 points [-]

right, well, it's just that 3^^^3 = 3^3^3^3^3...3^3^3 = 3^(3^3^3^3...3^3^3), for a certain number of threes. So, 3^^^3 is 3^(some odd power of three).

Comment author: Zack_M_Davis 02 May 2012 10:28:21PM 1 point [-]

Yes, thanks; I apologize for having misunderstood you earlier.

Comment author: VKS 02 May 2012 10:34:06PM 0 points [-]

That is entirely ok -- I am badly in need of sleep and may have failed to optimise my messages for legibility.