mwengler comments on Solving the two envelopes problem - Less Wrong

32 Post author: rstarkov 09 August 2012 01:42PM

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Comment author: mwengler 30 August 2012 02:31:16PM *  0 points [-]

Yes, I like your simplification.

To amplify it and make the results explicit, Suppose my envelope strategy is to flip a fair coin and
heads: R=$5 B=$10
tails: R=$10 B=$5.

Then
E(R) = E(B) = $7.50
E(B)/E(R) = E(B)/E(R) =1
E(R/B) = E(B/R) = 1.25