orthonormal comments on Decision Theories, Part 3.75: Hang On, I Think This Works After All - Less Wrong

23 Post author: orthonormal 06 September 2012 04:23PM

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Comment author: orthonormal 09 September 2012 01:07:52AM 2 points [-]

Uh, I don't understand you. |- □A->□□A is a very special case.

it follows from |-□A->A

That statement isn't true for general A!

Comment author: Decius 09 September 2012 05:06:33AM 0 points [-]

□A->A, (true statement, assuming a sound system)

but not

|- (□A->A)

□(□A->A) (confirm these are false statements)

but

|- □□A->A

and

|- □A-> □□A (these are statements you have made)

Comment author: orthonormal 09 September 2012 05:08:44AM 2 points [-]

|- □□A->A follows from the assumptions |- □A -> B and |- □B -> A; it's not a theorem in general.

Comment author: Decius 09 September 2012 01:37:56PM *  1 point [-]

Does it apply to (All A for which exist a B such that |- □A -> B and |- □B -> A)?

Is it possible to construct a B in general that meets those descriptions for an arbitrary statement? For example, B=" (a proof that a numbered proof of A implies B) and (a proof of a numbered proof of B implies A)" (B="( |- □A -> B) and ( |- □B -> A) ), or is a self-referential statement prohibited in sound systems?

Does B even have to be true, much less provable?

Comment author: orthonormal 09 September 2012 01:48:38PM 1 point [-]

To the first question, yes. That's what the top comment in this sequence proved (and Benja's reply proved much more elegantly).

To the second question, self-referential statements can't be ruled out in sufficiently powerful formal systems- that's what Gödel's Incompleteness Theorem uses!

To the third, again, if any formal system proves □A -> B and □B -> A, then it proves A and B.

Comment author: Decius 09 September 2012 07:58:44PM 1 point [-]

Consider the statement A "□A -> B and □B -> A" and the statement B "□A -> B and □B -> A and false"

Why are those two statements not provable in every system in which they can be written?