army1987 comments on Less Wrong Polls in Comments - Less Wrong

79 Post author: jimrandomh 19 September 2012 04:19PM

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Comment author: [deleted] 20 September 2012 10:47:36AM 2 points [-]

Is (the seconds' figure in my watch) mod 5 random enough?

Comment author: Luke_A_Somers 20 September 2012 01:43:12PM 1 point [-]

I used the least significant digit on my time-remaining-to-full-charge. And ended up propping up the most populated entry.

Comment author: BlazeOrangeDeer 25 September 2012 12:59:59AM *  1 point [-]

I needed 3 random bits (and threw out any overflow), which I got by checking whether arbitrary words or phrases I thought of had an even or odd number of letters. That's the most random completely mental (heh) way I know of, I wonder if there are others.

Comment author: Luke_A_Somers 25 September 2012 10:22:27AM 2 points [-]

... you could have done it more-reliably evenly by taking the mod 5 of the phrase/word length.

Comment author: [deleted] 25 September 2012 10:26:36PM 0 points [-]

Considering that the average word length in English is about five letters, I suspect that'd be quite far from being uniformly distributed.

Comment author: Luke_A_Somers 26 September 2012 01:39:01PM 1 point [-]

Average is irrelevant. What's relevant is the standard deviation.

Since standard deviation goes as the square root of the number of items being added, phrase length for any reasonably-sized phrase, so long as it wasn't a line of poetry, should be pretty evenly distributed.

Comment author: [deleted] 25 September 2012 10:23:00PM 0 points [-]

It's not obvious to me that it's unbiased. My gut feeling suspects that if I randomly chose a word it'd be more likely to have an odd than an even number of letters.