Kindly comments on Raising the forecasting waterline (part 1) - Less Wrong

33 Post author: Morendil 09 October 2012 03:49PM

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Comment author: mfb 13 October 2012 01:38:46PM 0 points [-]

To calculate the Brier score, you used >your< assumption that meteorites have a 1 in a million chance to hit a specfic area. What about events without a natural way to get those assumptions?

Let's use another example:

Assume that I predict that neither Obama nor Romney will be elected with 95% confidence. If that prediction becomes true, it is amazing and indicates a high predictive power (especially if I make multiple similar predictions and most of them become true).

Assume that I predict that either Obama or Romney will be elected with 95% confidence. If that prediction becomes true, it is not surprising.

Where is the difference? The second event is expected by others. How can we quantify "difference to expectations of others" and include it in the score? Maybe with an additional weight - weight each prediction with the difference from the expectations of others (as mean of the log ratio or something like that).

Comment author: Kindly 13 October 2012 03:31:40PM 0 points [-]

If the objective is to get better scores than others, then that helps, though it's not clear to me that it does so in any consistent way (in particular, the strategy to maximize your score and the strategy to get the best score with the highest probability may well be different, and one of them might involve mis-reporting your own degree of belief).