jmmcd comments on Checklist of Rationality Habits - Less Wrong

117 Post author: AnnaSalamon 07 November 2012 09:19PM

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Comment author: jmmcd 09 November 2012 08:25:48AM -2 points [-]

Well, we could choose factorise it as log(50000 dollars) = log(50000 dollar^0.5 * 1 dollar^0.5) = log(50000 dollar^0.5) + log(1 dollar^0.5). That does keep the units of the addition operands the same. Now we only have to figure out what the log of a root-dollar is...

the logarithm of a dollar

It's really just the same question again -- why can't I write log(1 dollar) = 0 (or maybe 0 dollar^0.5), the same as I would write log(1) = 0.

Comment author: satt 10 November 2012 01:17:06PM 0 points [-]

It's really just the same question again -- why can't I write log(1 dollar) = 0 (or maybe 0 dollar^0.5), the same as I would write log(1) = 0.

$1 = 100ยข. Now try logging both sides by stripping off the currency units first!