Kindly comments on SIA fears (expected) infinity - Less Wrong

6 Post author: Stuart_Armstrong 12 November 2012 05:23PM

You are viewing a comment permalink. View the original post to see all comments and the full post content.

Comments (13)

You are viewing a single comment's thread. Show more comments above.

Comment author: Kindly 13 November 2012 07:43:11PM *  0 points [-]

Actually, you're right about the infinite series of bets. Let N be the number of times Sleeping Beauty is to be woken up. Suppose (edit: on each day she wakes up) Sleeping Beauty is offered the following bets:

  • $10 if N=1, or $1 otherwise.
  • $10 if N=2, or $0.50 otherwise.
  • $10 if N=3, or $0.25 otherwise.
  • $10 if N=4, or $0.125 otherwise.
  • And so on.

In each individual bet, the second option has an infinite expectation, while the first has a finite expectation. However, if Sleeping Beauty accepts all the first options, she gets $10 every day she wakes up, for a total of $10N; if Sleeping Beauty accepts all the second options, she gets less than $2 every day she wakes up, for a total of $2N. Even though both options yield infinite expected money, this is still clearly inferior.

I suspect though, that this is a problem with the infinite nature of the experiment, not with Sleeping Beauty's betting preferences.

Comment author: Armok_GoB 14 November 2012 03:29:51AM 0 points [-]

That's not what I meant. I meant... ugh I'm really tired right now and can't think straight.

maybe:

Pot starts at 1$, each iteration she bets the pot against adding one dollar to it if N is greater than the number of iterations so far, with if needed the extra rule that if she gets woken up an infinite number of time she really gets infinite $.

To sleep deprived to check if the math actually works out like I think it does.