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AlexMennen comments on A utility-maximizing varient of AIXI - Less Wrong
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Oh right. But you still want the probability weighting to be inside the sum, so you would actually need=\frac{1}{\xi\left(\dot{y}\dot{x}_{%3Ck}y\underline{x}_{k:m_{k}}\right)}\sum_{q:q(y_{1:m_k})=x_{1:m_k}}%20U(q,y_{1:m_k})2%5E{-\ell\left(q\right)}%0A)
True. :)