wedrifid comments on Pascal's Muggle: Infinitesimal Priors and Strong Evidence - Less Wrong

43 Post author: Eliezer_Yudkowsky 08 May 2013 12:43AM

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Comment author: wedrifid 07 May 2013 01:49:18AM 1 point [-]

It takes log(3^^^^3) bits just to count that many things, so my absolute upper bound on the prior for an agent capable of doing this is 1/3^^^^3

Why does that prior follow from the counting difficulty?

Comment author: Schlega 07 May 2013 06:33:43AM 1 point [-]

I was thinking that using (length of program) + (memory required to run program) as a penalty makes more sense to me than (length of program) + (size of impact). I am assuming that any program that can simulate X minds must be able to handle numbers the size of X, so it would need more than log(X) bits of memory, which makes the prior less than 2^-log(X).

I wouldn't be overly surprised if there were some other situation that breaks this idea too, but I was just posting the first thing that came to mind when I read this.