DanielLC comments on Other prespective on resolving the Prisoner's dilemma - Less Wrong
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I mean the second one. Also, if I said the first one, I would mean the second one. They're the same by the definitions I use. The second one is more clear.
If the probability of an on-diagonal result is sufficiently high, and the benefit of an off-diagonal one is sufficiently low, that is all that's necessary for it to be worth while to cooperate.