Eliezer_Yudkowsky comments on Other prespective on resolving the Prisoner's dilemma - Less Wrong

11 Post author: Stuart_Armstrong 04 June 2013 04:13PM

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Comment author: Eliezer_Yudkowsky 05 June 2013 06:28:29AM 4 points [-]

If it is impossible to have off-diagonal results, that is a much stronger argument for cooperating than having it be improbable

If the probability is epsilon, then having the probability be zero is only an epsilon stronger argument. If you doubt this let epsilon equal 1/googolplex.