If a problem is NP-complete, then by definition, any NP problem can be solved in polynomial time by an algorithm which is given an oracle that solves the NP-complete problem, which it is allowed to use once. If, in place of the oracle, you substitute a polynomial-time algorithm which solves the problem correctly 90% of the time, the algorithm will still be polynomial-time, and will necessarily run correctly at least 90% of the time.

However, as JoshuaZ points out, this requires that the algorithm solve every instance of the problem with high probability, which is a much stronger condition than just solving a high proportion of instances. In retrospect, my comment was unhelpful, since it is not known whether there are any algorithms than solve every instance of an NP-complete problem with high probability. I don't know how generalizable the known tricks for solving SAT are (although presumably they are much more generalizable than JoshuaZ's example).