AlexMennen comments on Robust Cooperation in the Prisoner's Dilemma - Less Wrong

69 Post author: orthonormal 07 June 2013 08:30AM

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Comment author: AlexMennen 13 July 2013 09:37:58PM *  1 point [-]

They applied Lob's theorem correctly. "X is a theorem of PA" and "X is provable in PA" mean the same thing, and both are represented by ◻X. The antecedent of "if it's a theorem of PA that it's provable in PA that FB cooperates with me, then cooperate" would be represented as ◻(◻(FB(FB) = C)), but this never appears either in the code or in the antecedent for Lob's theorem. "FB(FB) = C" on its own, without the box, would mean it is true that fairbot cooperates with itself, not that PA can prove that fairbot cooperates with itself.