RolfAndreassen comments on Naturalistic trust among AIs: The parable of the thesis advisor's theorem - Less Wrong

24 Post author: Benja 15 December 2013 08:32AM

You are viewing a comment permalink. View the original post to see all comments and the full post content.

Comments (20)

You are viewing a single comment's thread.

Comment author: RolfAndreassen 15 December 2013 05:37:05PM 3 points [-]

Probably a stupid question: What is the difference between a proof, and a proof that something is provable? I understand the difference between a constructive proof and an existence proof, but in the case of proofs it seems that they should be the same.

Do we have any actual examples of proof-by-proving-provability?

Comment author: Benja 15 December 2013 06:23:47PM 2 points [-]

There is a way to write a predicate Proves(p,f) in the language of PA which is true if f is the Gödel number of a formula and p is the Gödel number of a proof of that formula from the axioms of PA. You can then define a predicate Provable(f) := exists p. Proves(p,f); then Provable(f) says that f is the Gödel number of a provable formula. Writing "A" for the Gödel number of the formula A, we can then write

PA |- Provable("A")

to say that there's a proof that A is provable, and

PA |- Provable("Provable("A")")

to say that there's a proof that there's a proof that A is provable. (Of course, PA |- A just says that there is a proof of A.)

On the metalevel, we know that

PA |- A

if and only if

PA |- Provable("A").

On the other hand, PA proves neither A -> Provable("A") nor Provable("A") -> A for general A.

(Hope that helps?)

Comment author: RolfAndreassen 15 December 2013 07:15:49PM 1 point [-]

Let me see if I can put that in my own words; if not, I didn't understand it. You are saying that humans, who do not operate strictly by PA, know that a proof of the existence of a proof is itself a proof; but a reasoner strictly limited to PA would not know any such thing, because it's not a theorem of PA. (PA being just an example - it could be any formal system, or at least any formal system that doesn't include the concept of proofs among its atoms, or concepts.) So such a reasoner can be shown a proof that a proof of A exists, but will not know that A is therefore a theorem of PA. Correct?

To me this seems more like a point about limitations of PA than about AI or logic per se; my conclusion would be "therefore, any serious AI needs a formal system with more oomph than PA". Is this a case of looking at PA "because that's where the light is", ie it's easy to reason about; or is there a case that solving such problems can inform reasoning about more realistic systems?

Comment author: CalmCanary 15 December 2013 08:31:41PM 2 points [-]

Strictly speaking, Lob's Theorem doesn't show that PA doesn't prove that the provability of any statement implies that statement. It just shows that if you have a statement in PA of the form (If S is provable, then S), you can use this to prove S. The part about PA not proving any implications of that form for a false S only follows if we assume that PA is sound.

Therefore, replacing PA with a stronger system or adding primitive concepts of provability in place of PA's complicated arithmetical construction won't help. As long as it can do everything PA can do (for example, prove that it can prove things it can prove), it will always be able to get from (If S is provable, then S) to S, even if S is 3*5=56..

Comment author: RolfAndreassen 16 December 2013 05:55:59PM *  0 points [-]

Let me see what happens if I put in a specific example. Suppose that

If 3*5=35 is a theorem of PA, then 3*5=35

is a theorem of PA. Let me refer to "3*5=35 is a theorem" as sentence 1; "3*5=35" as sentence 2, and the implication 1->2 as sentence 3. Now, if 3 is a theorem, then you can use PA to prove 2 even without actually showing 1; and then PA has proven a falsehood, and is inconsistent. Is that a correct statement of the problem?

If so... I seem to have lost track of the original difficulty, sorry. Why is it a worry that PA will assert that it can prove something false, but not a worry that it will assert something false? If you're going to worry that sentence 3 is a theorem, why not go straight to worrying that sentence 2 is a theorem?

Comment author: TobyBartels 18 December 2013 06:32:58PM 0 points [-]

We generally take it for granted that sentence 2 (because it is false) is not a theorem (and therefore sentence 1 is false), and the argument is meant to show that sentence 3 is therefore also not a theorem (even though it is true, since sentence 1 is false). This is a problem because we would like to use reasoning along the lines of sentence 3.

To see the real issue, you should replace sentence 2 with a conjecture whose truth you don't yet know but would like to know (and modify sentences 1 and 3 correspondingly). Now wouldn't you like sentence 3 to be a true? If you knew that sentence 1 was true, wouldn't you like to conclude that sentence 2 is true? Yet if you're PA, then you can't do that.

Comment author: xnn 15 December 2013 08:21:50PM 2 points [-]

"therefore, any serious AI needs a formal system with more oomph than PA"

The problem with that is that the same argument goes through in exactly the same way with any stronger system replacing PA. You might first try something like adding a rule "if PA proves that PA proves S, then S". This solves your original problem, but introduces new ones: there are now new statements that your system can prove that it can prove, but that it can't prove. Eliezer discusses this system, under the name PA+1, in You Provably Can't Trust Yourself .