savageorange comments on Even Odds - Less Wrong
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Comments (46)
A: 60% confidence B: 30% confidence
My intent is to demonstrate that, while the above is probably incorrect,
is not an adequate explanation to remember and get the right result out of, because the calculations I specified above are my genuine interpretation of your statements.
(this problem persists for every value of p and q, whether they total to above 1 or not)
Somebody replied with an explanation of how I was basically omitting the relativization of 'you' when considering what values to use.
That is, B should bet according to his confidence that he is correct, which in my case would be 70%..
Since you know it's wrong, how about you try again to make sense of it?
http://lesswrong.com/lw/jgv/even_odds/ad6y
Neither probability should be <50%, you take the probability that your opinion is the right one, not whether the proposition is true or false.
In your example B would be betting against his beliefs, thus the negative result.
The right calculation: A = 0.6 B = 0.7
Edit:
actually, it's sufficient that A and B sum to over 1. Since you can always negate the condition, the right calculation here is:
Also, apparently I can't use the retract button the way I wanted to use it.