rebellionkid comments on Einstein's Arrogance - Less Wrong

30 Post author: Eliezer_Yudkowsky 25 September 2007 01:29AM

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Comment author: lightpurpledye 17 July 2011 11:51:01AM 0 points [-]

What about the aliens who landed on earth, murdered Fred and then went away again? Or the infinite number of other possibilities, each of which has a very small probability?

What confuses me about this is that, if we do accept that there are an infinite number of possibilities, most of the possibilities must have an infinitesimal probability in order for everything to sum to 1. And I don't really understand the concept of an infinitesimal probability -- after all, even my example above must have some finite probability attached?

Comment author: rebellionkid 17 December 2011 02:54:29AM 1 point [-]

Just to point out what may be a nitpick or a clarification. It's perfectly possible for infinity many positive things to sum to a finite number. 1/2+1/4+1/8+...=1.

There can be infinitely many potential murderers. But if the probability of each having done it drops off fast enough you can avoid anything that is literally infinitesimal. Almost all will be less than 1/3^^^^^^3 of course, but that's a perfectly well defined number you know how to do maths with.

Comment author: Daemon 14 September 2013 07:34:06AM *  -1 points [-]

Hate to nitpick myself, but 1/2+1/4+1/8+... diverges (e.g., by the harmonic series test). Sum 1/n^2 = 1/4 + 1/9 + ... = (pi^2)/6 is a more fitting example.

An interesting question, in this context, is what it would mean for infinitely many possibilities to exist in a "finite space about any point that can be reached at sub-speed of light times." Would it be possible under the assumption of a discrete universe (a universe decomposable no further than the smallest, indivisible pieces)? This is an issue we don't have to worry about in dealing with the infinite sums of numbers that converge to a finite number.

Comment author: Bayeslisk 14 September 2013 07:54:59AM 2 points [-]

That's not correct at all. sum(1/2^n)[1:infinity] = 1.

Comment author: Daemon 14 September 2013 08:06:08AM 4 points [-]

Oops, misread that as sum(1/(2n))[1:infinity] (which it wasn't), my bad.