owencb comments on How to treat problems of unknown difficulty - Less Wrong

13 Post author: owencb 30 July 2014 11:27AM

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Comment author: owencb 18 September 2014 11:54:33AM 1 point [-]

The end of your example gets hard to follow. In particular I don't know what this means:

goals with pP ( -log(P) )in the 2-4 range

On the other hand it sounds like you're reaching a qualitatively correct solution.

Comment author: Decius 18 September 2014 10:51:54PM 1 point [-]

pP is the negative logarithm of P, the probability of the 'jackpot payoff'.

If money were of linear value, I would be ambivalent about investing $10k in a startup that had a .01 chance of making a million dollars; for P=.01, pP=2