I'm saying if not provable(p) then (if provable(p) then q)
You aren't saying that though. In the post where you numbered your arguments, you said (bolding mine)
if not(provable(P)) then provable(if provable(P) then P)
which is different, because it has an extra 'provable'.
So then here's a smaller lemma: for all x and all q:
If(not(x))
Then provable(if x then q): by definition of if-then
So replace x by Provable(P) and q by p.
Where's the flaw?
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