Grothor comments on Entropy and Temperature - Less Wrong

26 Post author: spxtr 17 December 2014 08:04AM

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Comment author: Grothor 18 December 2014 05:38:47AM *  2 points [-]

your final answer isn't right

You're right. That should be ε, not E. I did the extra few steps to substitute α = E/(Nε) back in, and solve for E, to recover DanielFilan's (corrected) result:

E = Nε / (exp(ε/T) + 1)

I used S = log[N choose M], where M is the number of excited particles (so M = αN). Then I used Stirling's approximation as you suggested, and differentiated with respect to α.

Comment author: spxtr 18 December 2014 06:15:29AM 0 points [-]

Good show!