RolfAndreassen comments on Open Thread, Jun. 29 - Jul. 5, 2015 - Less Wrong
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How do I add probabilities? Say I have 23% chance of A, and 48% chance of B, what are the chances of either? I used to think I would just add the probabilities, intuitively...then I came across problems where it sums to greater than 100%, but it's not certain. If you think like I used to think, this abstract example won't help you. So I'll give a descriptive version below. For anyone who can explain it to me, feel free to skip the next part:
Say Jimmy wants to destroy an unwanted statue. From research on statue destruction, he believes there is a 95% chance that the statue will be destroyed if he places it in front of the train. He also knows from research that if he puts a rope around it and drops it from a height, the force of the snap back will break the statue in half. He reasons that he can put a rope around it then attach that rope to the tracks, so that when the train comes, the snapping force will apply with the same destructive probability that the research cites - 96%. If the statue isn't destroyed, Jimmy is going to have to take care of the pieces, which will be a lot of work, so Jimmy wants to know what he's getting into. I wonder if there a way to combine the probabilities for an overall probabiltiy given that both apply?
You take the probability of A not happening and multiply by the probability of B not happening. That gives you P(not A and not B). Then subtract that from 1. The probability of at least one of two events happening is just one minus the probability of neither happening.
In your example of 23% and 48%, the probability of getting at least one is
1 - (1-0.23)*(1-0.48) = 0.60.
Only if A and B are independent.