Kapow comments on Beautiful Math - Less Wrong

24 Post author: Eliezer_Yudkowsky 10 January 2008 10:43PM

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Comment author: Kapow 11 January 2008 12:25:10AM 0 points [-]

To go even further, if you take the sequence A[k] = k^n and, for each n, take differences until you reach a constant, then the list A[n] of those constants is n factorial (n!).