Ken_Houghton comments on Expecting Beauty - Less Wrong

16 Post author: Eliezer_Yudkowsky 12 January 2008 03:00AM

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Comment author: Ken_Houghton 17 January 2008 04:40:37PM 0 points [-]

Isn't the last value in the sequence definitionally zero for the first five terms, reducing the entire first term to zero as well and leaving only the n^2?

Does this mean that if we gave you (1, 4, 9, 16, 25, 36...) you would claim the next value in the sequence was 6! plus 49??