IlyaShpitser comments on Stupid questions thread, October 2015 - Less Wrong

3 Post author: philh 13 October 2015 07:39PM

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Comment author: Lumifer 16 October 2015 03:21:11PM *  3 points [-]

The recent talk about alien constructs and so Dyson spheres got me wondering.

Assuming their existence, why do we expect to see Dyson spheres in other star systems? A new Dyson sphere (that is, the star + Dyson sphere system) would not emit much anything and so would be invisible. Of course, the energy has to go somewhere and even superadvanced aliens -- assuming they haven't developed all new superadvanced physics -- will have a lot of waste heat. That heat, we expect, would be dumped into surrounding space as some sort of radiation and so we would see it.

That leads me to two stupid questions (note that we are talking at the star-system scale):

  • Can you dump waste heat directionally? If you built a Dyson sphere and became invisible at interstellar distances, can you radiate your heat signature as a beam and continue to avoid being seen?

  • If you have a handy black hole around, can you dump the waste heat into a black hole? What that would look like?

P.S. If the Dyson sphere functions only as an energy source it would be invisible, seems to me. Imagine a scenario where aliens come to a star system, build a Dyson sphere around the star, and then arrange for all that energy to be narrow-beamed to neighbouring star systems where it will be collected and used. The point is that the energy is used elsewhere, so the Dysoned star emits very little and unless you're in the beam you don't see it. Would that work?

Comment author: IlyaShpitser 16 October 2015 04:11:46PM *  3 points [-]

Not sure it makes sense thermodynamically to deal with waste heat that way (if you are transmitting "waste heat" in a narrow beam, you are basically just transmitting energy in a narrow beam, and so it's not waste heat anymore -- you can get useful work out of it).


edit: I suppose the question is: what % of the star's outgoing energy can we harness in principle, such that waste heat is hard to tell apart from background, and we completely hide that the star is there. For example, in the limit, if you just used a little of the star's energy to redirect all the rest into a black hole, will the waste heat just from the redirection effort be detectable? If so, we can't hide a star, the best we can do is not use too much energy, so the star looks like a normal star with no life in the system (but evil aliens can still come and check it out, since they know a star is there). If not, maybe we can harness some bigger % on the way into the black hole. If so, what % is physically possible? I don't know.


I feel like physicists already worked out that you can't hide stars, but I don't know the literature.

Comment author: CellBioGuy 17 October 2015 09:37:20PM *  1 point [-]

I suppose the question is: what % of the star's outgoing energy can we harness in principle, such that waste heat is hard to tell apart from background

You can never have the temperature of outgoing radiation indistinguishable from the cosmic background, since energy is being generated by the star and in equilibrium more energy must leave than enters from the background.

The CMB reads as ~2.76k. Let's say you wanted to radiate the entire energy output of a star at 3.76 k. That means the flux out equals the star's flux plus the CMB flux in. For a star like the sun, the surface area of material required comes to a sphere a fifth of a light year (13000 AUs) in radius to dissipate a solar luminosity of energy (divide quantity of radiator material by the fraction of the solar luminosity you want to use, but keep in mind having the radiators closer than a 5th of a light year would probably be pointless since they'd be heated up by the sun) (also keep in mind such an object would look as large as the full moon 44 light years away and as wide as Jupiter in our sky 2,000 light years away). For ten kelvin, a sphere 0.025 light years or 1560 AUs in radius. For 50 kelvin, 62 AUs (twice as large as Neptune's orbit).

Of course, there's also the starlight flux of all the other nearby stars, which makes this worse for very low temperatures.

(Calculations done using energy out = energy in from CMB + solar flux, and the definition of blackbody radiation)

EDIT: I should go over some astronomy papers and figure out what amounts of material typically produce observable infrared excesses.

Comment author: Romashka 17 October 2015 09:22:21AM 0 points [-]

What does it mean to hide a star? Would it not be 'visible' by having gravity?

Comment author: RichardKennaway 17 October 2015 07:41:19PM 1 point [-]

What does it mean to hide a star? Would it not be 'visible' by having gravity?

That explains dark matter — vast alien civilisations that leak nothing but gravity. And the microwave background.

Comment author: CellBioGuy 17 October 2015 08:52:17PM *  1 point [-]

No it doesn't. Microwave background intensity is uncorrelated with imputed dark matter density in a given direction.