Insert_Idionym_Here comments on Feynman Paths - Less Wrong

14 Post author: Eliezer_Yudkowsky 17 April 2008 06:32AM

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Comment author: Insert_Idionym_Here 16 December 2011 11:51:01PM 0 points [-]

Okay, so where did those arrows come from? I see how the graph second from the top corresponds to the amount of time a particle, were particles to exist, would take if it bounced, if it could bounce, because it's not actually a particle, off of a specific point on the mirror. But how does one pull the arrows out of that graph?

Comment author: arundelo 17 December 2011 01:30:01AM *  3 points [-]

Feynman talks about this between 59:33 and 60:32 of part one of his 1979 Douglas Robb lectures.

Between 29:41 and 36:27 of part two, he draws the "arrows" diagram on the chalkboard.

If you find this topic interesting, you'll enjoy all four parts of the lecture series. See also 63:26 to 63:35 of part one, which is relevant to your other question.

Edit: To explicitly answer your question, the angle of each arrow is proportional to the height of the graph above that arrow. Note that different heights on the graph can correspond to identical angles, since (for example) 0 radians, 2pi radians, and 4pi radians are all the same angle.

Comment author: Insert_Idionym_Here 17 December 2011 05:44:49AM 0 points [-]

Thank you very much.