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Robert4 comments on The Cartoon Guide to Löb's Theorem - Less Wrong

12 Post author: Eliezer_Yudkowsky 17 August 2008 08:35PM

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Comment author: Robert4 18 August 2008 05:58:27AM 0 points [-]

Opps, I made an error when I said: "It is clear that (X->Y)->X does not imply (not X)->X, so your little trick doesn't work." This is false. This implication does exist, so we get:

((not â—ťC)->(â—ťC))

This sentence is true just in case C is in fact provable, so we don't have a problem with your 2=1 cases.