Sorry, I have not been specific enough. Each of my 3^^^^3, 3^^^^3-1, 3^^^^3-2, etc. examples are mutually exclusive (but the sofa is part of the "0" case). While they might not span all possibilities (not exhaustive) and could thus sum to less than one, they cannot sum to higher than 1. As I see it, the weakest assumption here is that "more persons/pigs is less or equally likely". If this holds, the "worst case scenario" is epsilon=1/(3^^^^3) but I would guess for far less than that.