I have sympathy with both one-boxers and two-boxers in Newcomb's problem. Contrary to this, however, many people on Less Wrong seem to be staunch and confident one-boxers. So I'm turning to you guys to ask for help figuring out whether I should be a staunch one-boxer too. Below is an imaginary dialogue setting out my understanding of the arguments normally advanced on LW for one-boxing and I was hoping to get help filling in the details and extending this argument so that I (and anyone else who is uncertain about the issue) can develop an understanding of the strongest arguments for one-boxing.
Consider the following two mechanisms for a Newcomb-like problem.
A. T-Omega offers you the one or two box choice. You know that T-Omega used a time machine to see if you picked one or two boxes, and used that information to place/not place the million dollars.
B. C-Omega offers you the one or two box choice. You know that C-Omega is con man, that pretends great predictive powers on each planet he visits. Usually he fails, but on Earth he gets lucky. C-Omega uses a coin flip to place/not place the million dollars.
I claim the correct choice is to one box T-Omega, and two box C-Omega.
Can someone explain how it is in the “original” problem?
That is, what mechanism does the “real” Omega use for making his decision?
There is a contradiction here between "lucky" and "coin flip". Why does he get lucky on Earth?
In the original problem Omega runs a simulation of you, which is equivalent to T-Omega.