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GuySrinivasan comments on Zeckhauser's roulette - Less Wrong Discussion

11 Post author: cousin_it 19 January 2012 07:22PM

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Comment author: GuySrinivasan 20 January 2012 12:05:23AM 1 point [-]
  • if you just set up the lottery equivalences they simplify to U(life - $X) = U(life - $Y) pretty much implying that whatever the correct choices of X and Y happen to be, they're equal.
  • the setup is very dependent on the exact probabilities: if you change the cases to 10-shooters where you can remove one from five bullets or where you can remove two from two bullets, there's not a proof that the amounts you should pay are equal.
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