Consider the following two mechanisms for a Newcomb-like problem.
A. T-Omega offers you the one or two box choice. You know that T-Omega used a time machine to see if you picked one or two boxes, and used that information to place/not place the million dollars.
B. C-Omega offers you the one or two box choice. You know that C-Omega is con man, that pretends great predictive powers on each planet he visits. Usually he fails, but on Earth he gets lucky. C-Omega uses a coin flip to place/not place the million dollars.
I claim the correct choice is to one box T-Omega, and two box C-Omega.
Can someone explain how it is in the “original” problem?
That is, what mechanism does the “real” Omega use for making his decision?
Usually he fails, but on Earth he gets lucky. C-Omega uses a coin flip to place/not place the million dollars.
There is a contradiction here between "lucky" and "coin flip". Why does he get lucky on Earth?
Can someone explain how it is in the “original” problem?
In the original problem Omega runs a simulation of you, which is equivalent to T-Omega.
I have sympathy with both one-boxers and two-boxers in Newcomb's problem. Contrary to this, however, many people on Less Wrong seem to be staunch and confident one-boxers. So I'm turning to you guys to ask for help figuring out whether I should be a staunch one-boxer too. Below is an imaginary dialogue setting out my understanding of the arguments normally advanced on LW for one-boxing and I was hoping to get help filling in the details and extending this argument so that I (and anyone else who is uncertain about the issue) can develop an understanding of the strongest arguments for one-boxing.