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RolfAndreassen comments on Open Thread, October 7 - October 12, 2013 - Less Wrong Discussion
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Taking his 8km/sec speed and 100km height as accurate, the energy to lift one kilogram that high on a ballistic arc (ignoring air resistance and the motion of the Earth's surface) is mgh = 1kg*100km * (1000m/km) * (10 m/s^2) =1e6 J. The energy to accelerate it to orbital speed is 0.5mv^2 = 0.5*1kg*(8000m/s)^2 = 32e6 J. First pass, then, his reasoning seems accurate. Am I oversimplifying? What is your calculation?